Rangerang
New Member
- Joined
- Aug 1, 2014
- Messages
- 13
- Reaction score
- 0
- Points
- 1
- Vehicle Year
- 1988
- Make / Model
- Ford
- Engine Type
- 2.9 V6
- Transmission
- Manual
- 2WD / 4WD
- 4WD
On my '88 Ranger I replaced the 7.5 inch rear axle with an 8.8 inch. The original had the SMALL (3.5 inch) bolt circle diameter and the new has the LARGE (4.25 inch) bolt circle diameter. The Spicer 2-2-1379 yoke is the ideal fit for the 8.8" but it's for 1310 series U-joint. The original yoke (C2-2-501 now 2-2-1049) used a series 1210 U-joint, as does the driveshaft. After hours of searching I haven't found a 1210 to 1310 conversion U-joint so I'm stuck. Bottom line, I need to connect a 1210 driveshaft to a LARGE (4.25") yoke. It could be a LARGE yoke that uses a 1210 U-joint, a 1210 to 1310 conversion U-joint, a different axle, or fabricating something on the existing axle. The truck is an '88 Ranger, extended cab, long bed. The axle is from a '91 unknown Ranger. Any ideas?