will either parallel or series wiring suck more power than each?

[gertsdsbs]

So does parallel suck more power than series wiring or vice versa? Or do they suck the same power? and if anyone knows, does having one over the other create better sound?

Specs: 1986 single cab ranger
two kicker shallow 10"s
Thanks!!!!!!!!!!!!!!!!!

 

[snomaker321]

it depends on the amps, subs, etc.
are your subs 2 or 4 ohm?
what amp?

Basically, if you wire say 2 4ohm subs in parallel it will create a 2ohm load on the amp and will draw more power.

So I guess parallel will draw more power, but more importantly you have to match your amp and subs to get the right amount of power with the correct resistance so you dont blow anything up.

 

[baxtej44]

it depends on the amps, subs, etc.
are your subs 2 or 4 ohm?
what amp?

Basically, if you wire say 2 4ohm subs in parallel it will create a 2ohm load on the amp and will draw more power.

So I guess parallel will draw more power, but more importantly you have to match your amp and subs to get the right amount of power with the correct resistance so you dont blow anything up.

yes, you first have to make sure your amp is stable at whatever ohms you are setting up your subs with (some aren't stable with 1, and i would guess at least SOME aren't stable at 2... read your manufacturer's documents)...

also, make sure that your power rating at the desired ohm resistance isn't too much so you don't blow your sub.


in a short answer, wiring in parallel CAN and will get you a lower ohm rating, which will have more watts, however if all three sides of your equipment (sub/speaker, amp, and wiring) can't keep up with it, something will give.

 

[gertsdsbs]

ALRIGHT! guess im gonna go with series since my truck doesn't put that much power. THANKS!!! oh by the way the subs are 4ohm.

 

[4x4fun]

ALRIGHT! guess im gonna go with series since my truck doesn't put that much power. THANKS!!! oh by the way the subs are 4ohm.

if you run your subs in series your gonna have an 8 ohm load.

parrell you divide by two

series you add the ohms together.

i really dont think your amp is 8 ohms stable. and normally the higher your ohms load the less your amp can put out. ohms is resistance. so the more you have, the harder it is for you amp to push.

 

[snomaker321]

ALRIGHT! guess im gonna go with series since my truck doesn't put that much power. THANKS!!! oh by the way the subs are 4ohm.

by your truck, do you mean your going to run them off of your head unit? there is no way a headunit will have enough juice to run a sub. You need an amp.

Im going to assume your subs are CompVTs

Your subs can handle 400watts rms each, but you probably dont need that much. I dont know how low i'd go, ill let someone else chime in on that.

anyway, you ideally want a mono amp thats 2ohm stable and puts out 800 watts rms at 2ohms. Or, a 2 channel amp that puts out 400 watts rms at 4ohms for each channel.

Again, these numbers would be ideal but you should be fun with less. An amp with that much power is $$$

 

[gertsdsbs]

I have a 600 rms 4ohms amp. I know its not enough for two but running 300 each should be enough. or am i wrong?

 

[Scotty J.]

parrell you divide by two

That is incorrect, and a very dangerous statement.

The formula for Parallel in Ohms law is:
1/(1/R1+1/R2+1/R3) etc...

Here's the problem, put an 8ohm in parallel with a 4ohm.

According to your math, it should be 6ohms. Instead it's 2.7ohms. Get ready for the fire.

 

[gertsdsbs]

wait, what? fire?

 

[Scotty J.]

wait, what? fire?

He said divide by two. So in my example you have 12 ohms, divide by two is 6 ohms. Using Ohms law, P=I²R you would take the square root of (600/6)
600/6=100
√100=10 amps

Now, let's look at what the amperage would really be.
Since ohms law requires 1/(1/R1+1/R2) you take the inverse of R1 (8ohms) and add it to the inverse of R2 (4ohms):
1/8=.125
1/4=.25
.125+.25=0.375
1/0.375=2.7ohms (actual resistance)
600/2.7=222
√222=15 amps (50% increase in the output from what your amp is rated for=fire)

 

[4x4fun]

That is incorrect, and a very dangerous statement.

first, any one asking about running wire P or s doesnt need all that. thats what call techcinal jargon. and doesnt help him.

why you would have a 8 ohms sub and a 4 ohms sub......idk but your shit should burn anyway


so for the OP

if you have (2) 3ohm subs P = 1.5 S =6

if you have (2) 4 ohms subs P=2 S=8

if you have 2 2ohm subs P=1 S=4

noticing a trend.

isnt "cut it in half" alot easer to under stand for a noob ( no offence) then dlifhsdalifhsdaligfhsdaligfhsdligfhlgihdlgifhda;gfjda;fhda;fihw

of numers and math crap .


now......

Using Ohms law, P=I²R

^^^^that equation^^^^^^

is for finding watts not ohms

secondly : it stands for watts = amps ^2 x ohms

idk what math your using that takes an equation to find watt and ends up with 10 amps as answer

you took the squre root of his max watts output, which isnt even "AMP" measurement the equation

and his theoretical amps using correct math is 42.857 BTW!!!!

and yea im not done......but im gonna stop

the point is. i might not say things 100% correct 100% of the time.........how ever helping some one understand a concept is bettter then getting my wording correct.

also you wanna call me out have yours correct.

 

[Scotty J.]

^^^^that equation^^^^^^

is for finding watts not ohms

P=I²R is a formula. If you don't know how to use that formula to find Resistance or Amperage then you don't need to be hooking up stereo equipment for anyone but yourself, much less giving people advice. You will be damaging their shit.

Show me the math that discredits what I posted. I'll be happy to go through it slower so that you can understand it.

 

[gertsdsbs]

Damn wtf, this is some rocket science stuff.lol

 

[Scotty J.]

Damn wtf, this is some rocket science stuff.lol

No, it's just exact. Be afraid of anyone that tells you to just divide by two when connecting stereo equipment, it is incorrect and could add to big time problems down the road.

You have a 600w (RMS) amp that supports a load of 4ohms. If you put 2 8ohm speakers in parallel, you will be using the amp at its peak performance.

 

[4x4fun]

P=I²R is a formula.

well its an equation for one that why it has the "=" sign

an forumal is like ratios or chemial compounds

now.......

to find RESISTANCE

you have three options

P/ I^2

E^2/P

I/E

to find AMPS

again you have three options

E/R

P/E

SQR (P/R)


notice how i didnt say I^2 times R

thats becasue you cant use it to find AMPS orrrrr RES. casue its for finding watts and watts alone.

secondly you didnt even finish the equation you used. you stopped half way thur.

P=I²R you would take the square root of (600/6)
600/6=100
√100=10 amps

you tried to use sqr 600W/6ohms to find amps.....wich does give you 10

how ever you then have to put it in the equation

P= 10^2*6 .........10 squared is 100 sooooo

P=100 times 6........which is 600

which equals P=600
"P" is a unit offfffff watts
so he would have 600 watts not 10 amps

any questions?????????????