will either parallel or series wiring suck more power than each?

[Scotty J.]

Wow, I'm getting dizzy trying to keep up.

Here's my math, feel free to check it.

P=I²R
I=5
R=2
P=50

I=√P/R
P=50
I=5
R=2
50/2=25
√25=5
I=5

R=P/I²
P=50
I=5
I²=25
50/25=2
R=2

 

[4x4fun]

i sorry edit soo messed up my math its right now lol

 

[4x4fun]

if you know your watts to find "I" then why are you useing "I" to find out what your watts are?

 

[Scotty J.]

if you know your watts to find "I" then why are you useing "I" to find out what your watts are?

It's called design. Please don't give advice if you don't understand the laws of physics.

 

[4x4fun]

It's called design. Please don't give advice if you don't understand the laws of physics.

lets forget physics id like you to learn to finish an equation before we get into physics

if use a number to find another number...........just to find the number you allready know thats retarded....... if you already know what your looking for why look for it some more????????

 

[Scotty J.]

if use a number to find another number...........just to find the number you allready know thats retarded....... if you already know what your looking for why look for it some more????????

Thank you for qualifying my point.

 

[4x4fun]

Thank you for qualifying my point.

first were you looking for "quantifying"

second: the equation you gave to prove me "wrong" or mistaking.. was the wrong one. and you didnt even finish the equation you miss use. and then you tried to use the "right math" to prove me wrong again, but you based it against a miss use equation. that wasnt even complete in the first place.


so i have to ask what is your point in all this.......to say i mis spoke in the interest of keeping it simple so a noob could understand.

 

[snomaker321]

first were you looking for "quantifying"

second: the equation you gave to prove me "wrong" or mistaking.. was the wrong one. and you didnt even finish the equation you miss use. and then you tried to use the "right math" to prove me wrong again, but you based it against a miss use equation. that wasnt even complete in the first place.


so i have to ask what is your point in all this.......to say i mis spoke in the interest of keeping it simple so a noob could understand.

His first equation was 100% correct.

P= I^2 x R
P= 600 watts
R= 6 ohms
P/R = I^2
600/60 = I^2
I= sqrt(100)
I = 10 amps

looks good to me

 

[snomaker321]

lets forget physics id like you to learn to finish an equation before we get into physics

And just putting it out there, this is all physics. Physics that you learn in your junior year of high school.

 

[snomaker321]

I have a 600 rms 4ohms amp. I know its not enough for two but running 300 each should be enough. or am i wrong?

is it a 1 or 2 channel amp? If its only 1, is it 2ohm stable? Actually to make things easier, what brand and model amp do you have?

Depending on the amp, you MIGHT be able to pull off wiring them in parallel, but you have to be careful because they will be overpowered.

Really, that amp isnt going to work for you. You either need a different amp or the 2 ohm versions of the subs. If they were 2 ohm, you could wire them in series and get 300 watts each but if its a mono amp theres no way you can put a 4 ohm load on the amp with those 2 subs.

 

[4x4fun]

His first equation was 100% correct.

P= I^2 x R
P= 600 watts
R= 6 ohms
P/R = I^2
600/60 = I^2
I= sqrt(100)
I = 10 amps

looks good to me

yes but P=I^2 x R

is to find watts. the equation he did or ended up making should have said was I= SqR of (P/R).

so he quoted one equation then used another. he also used made up numbers then used them against real numbers to come up with an answer.

then tried used another law to say the actually actualy amps were 50% over his made up numbers.

when using ohms law against the amp. amps = watts/volts or A= 600/14 you get 42.857

which one is wellllll over the 15 amp he said it should have

more so iv been around long enuff to know a true 600rms amp is more likely to have two 20 amp fuses on the back vers the 15 he said it should have

 

[snomaker321]

yes but P=I^2 x R

is to find watts. the equation he did or ended up making should have said was I= SqR of (P/R).

so he quoted one equation then used another. he also used made up numbers then used them against real numbers to come up with an answer.

then tried used another law to say the actually actualy amps were 50% over his made up numbers.

when using ohms law against the amp. amps = watts/volts or A= 600/14 you get 42.857

which one is wellllll over the 15 amp he said it should have

more so iv been around long enuff to know a true 600rms amp is more likely to have two 20 amp fuses on the back vers the 15 he said it should have

yes but thats not how the equation is known, thats just a rearranged version of it. it doesnt really matter, i was just saying that his initial math was correct.

i dont know what he means by design, ive never heard of it. but then again, im only a senior in high school. I think he was just showing that no matter how you rearranged the equation and whatnot everything came out the same

after that, i lost you guys. Its too late for me to be comprehending all these numbers being thrown around. Maybe i'll take a look at it tomorrow. I think you both know what you are talking about but just dont understand each other

 

[4x4fun]

yes but thats not how the equation is known,

there are actually 12 equations depening on what you looking for.

and i got super lost when i dumbed down the way to figure out ohms. and i was getting equations ending in amps ect........ so i had to re ask his point, and i still dont know what he was trying to prove really.

o well

 

[snomaker321]

there are actually 12 equations depening on what you looking for.

and i got super lost when i dumbed down the way to figure out ohms. and i was getting equations ending in amps ect........ so i had to re ask his point, and i still dont know what he was trying to prove really.

o well

Im just saying when you learn it, you learn P=I^2 x R not I= sqrt(P/R). Im not saying the latter is wrong, because its not. Im just saying theres no need to know 12 equations when only need like 4. You just plug in what you know and solve for the unknowns.

 

[snomaker321]

well its an equation for one that why it has the "=" sign

an forumal is like ratios or chemial compounds

now.......

to find RESISTANCE

you have three options

P/ I^2

E^2/P

I/E

to find AMPS

again you have three options

E/R

P/E

SQR (P/R)


notice how i didnt say I^2 times R

thats becasue you cant use it to find AMPS orrrrr RES. casue its for finding watts and watts alone.

secondly you didnt even finish the equation you used. you stopped half way thur.




you tried to use sqr 600W/6ohms to find amps.....wich does give you 10

how ever you then have to put it in the equation

P= 10^2*6 .........10 squared is 100 sooooo

P=100 times 6........which is 600

which equals P=600
"P" is a unit offfffff watts
so he would have 600 watts not 10 amps

any questions?????????????

and here, his power would be 600 watts and his current would be 10 amps. You just did what he did backwards. I dont see what you were getting at. You started with 600 watts to find that you had 10 amps then put it back in to find you had 600 watts. Which is basically what he does on the 1st post of the second page.

I dont even know why im bothering right now. You both know what youre talking about but just have different ways of thinking