Ring Gear Questions

[LittleBigFoot]

Either I cant find it, or there's no stamp or tag on my 85 Wagoneer D44. I'm trying to figure out the ring gear ratio. Any particular method for figuring it out? I've looked on line but there's a number of different ratios and I don't know engine size for the Jeep the axle came out of.

Thanks,
Adam

 

[Hahnsb2]

I believe you can figure it out by dividing the amount of teeth on the ring by the amount teeth on the pinion. It can also be stamped on the ring gear itself.

 

[LittleBigFoot]

Thanks Hahnsb2
I guess that's tomorrows project now

 

[baddis]

put tires on it , make a mark , spin the yoke and count the revolutions of the yoke to 1 revolution of the tire . this will get you close enough to know.

 

[LittleBigFoot]

I'd love to do that, but I don't have the wheels/meats yet.
It' looks to be 2.73:1
I was prayin it would be 3.73:1 to match my rear so I could at least get it in and running before I re-gear.

Bleh, I'll still count and divide tomorrow and see for sure.

Thanks for the help guys

 

[james99]

you dont need tires just mark the drums or disks

 

[LittleBigFoot]

There's a thought

The only problem is that when I crank the ujoint by hand only the drivers side turns.

The passenger side has a brake issue I'm yet to address. It turns when I move it by hand and it roates the ujoint, but when I turn the ujoint it doesnt turn the passenger side. Is that typical?

 

[thegoat4]

There's a thought

The only problem is that when I crank the ujoint by hand only the drivers side turns.

The passenger side has a brake issue I'm yet to address. It turns when I move it by hand and it roates the ujoint, but when I turn the ujoint it doesnt turn the passenger side. Is that typical?

Then rotate the pinion until the driver's side wheel turns 1/2 a turn. However many turns you got from the pinion is your ratio.

edit: NO!!! Rotate the pinion until the driver's side turns two full revolutions. Then the number of revolutions at the pinion will be your ratio. I divided the wrong way. Sorry.

 

[Sunk]

There's a thought

The only problem is that when I crank the ujoint by hand only the drivers side turns.

The passenger side has a brake issue I'm yet to address. It turns when I move it by hand and it roates the ujoint, but when I turn the ujoint it doesnt turn the passenger side. Is that typical?

Sounds normal I think... Its an open differential right?

 

[baddis]

Then rotate the pinion until the driver's side wheel turns 1/2 a turn. However many turns you got from the pinion is your ratio.

no it would still be 1 full revolution.1/2 is 1/2 no mater what way you look at it. with or without a tire it still needs to go around 1 full revolution.

 

[LittleBigFoot]

yeah sunk,
It's open.
Could it be a problem with the hubs? They're the selec-trac vaccume hubs locked in full time. We could have damaged something when pulling it out. hmmmm


Thanks

 

[Hahnsb2]

no it would still be 1 full revolution.1/2 is 1/2 no mater what way you look at it. with or without a tire it still needs to go around 1 full revolution.

No, not if one side isnt turning. If you stop one tire with an open the diff the other tire will spin twice as fast... Or if you're going around a corner and the inside tire slows down the 30% the outside MUST speed up 70% to equal 100%. I know I didnt explain it very well but thats how it works.

 

[baddis]

No, not if one side isnt turning. If you stop one tire with an open the diff the other tire will spin twice as fast... Or if you're going around a corner and the inside tire slows down the 30% the outside MUST speed up 70% to equal 100%. I know I didnt explain it very well but thats how it works.

speed does not matter it still has to turn 1 full revolution if the other is not turning its not turning plain and simple.

 

[Todd]

I don’t think you are getting it. If one axle shaft does not spin then one side gear is not spinning. When this is the case the other side gear spins a greater rotational amount in turn the shaft and whatever after that turns the same amount. Thus the rotational displacement of the one side is greater by a factor of 2. That side will still rotate directly from the pinion input. If the drive shaft is spinning at a rate X and assume no gear reduction at the diff then the free side will spin that rate X times 2.

So for doing the spin and count method of the ring and pinion if one side spins then for one input rotation at the pinion will equal 2 rotations of the tire.

 

[rickcdewitt]

yep^^^ if you peel out with only one tire and the speedo says 45 the tire is going 90!