4.0l OHV engine runs 9.0:1 compression ratio, multiplier for sea level compression test is 18
18 X 9 = 162
So 162 PSI on compression test should be expected on lower mile COLD engine
18 is from 15 psi air pressure at sea level(14.7psi), + 3 for mechanical action of engine compressing the air
I pulled this from a recent thread. my question is mostly about the "multiplier".
I'm fully versed in using the volumes to calculate CR, I want to do it backwards.
I'm trying to get a handle on determining the compression ratio from the compression test results.
theoretical 175 PSI cranking divided by "multiplier" should get me close to CR,,,right?
getting the correct value for the multiplier is what I want. in the above example it's just local pressure plus 3.
I realize that atmospheric pressure will affect the results, a check of the local weather should get me close on that number.
yes, I'll convert the Hg to PSI. (if I can find my old physics book)
the +3 for mechanical action has me wondering,, is that a "standard" for a healthy engine?
any other variables?
if I use 175 psi test results, and 14.5psi local pressure, I'm at 650' above sea level,
175 PSI /(14.5 + 3) = 10 CR
I realize the accuracy may be a bit off, just trying to get close.
comments anybody?
18 X 9 = 162
So 162 PSI on compression test should be expected on lower mile COLD engine
18 is from 15 psi air pressure at sea level(14.7psi), + 3 for mechanical action of engine compressing the air
I pulled this from a recent thread. my question is mostly about the "multiplier".
I'm fully versed in using the volumes to calculate CR, I want to do it backwards.
I'm trying to get a handle on determining the compression ratio from the compression test results.
theoretical 175 PSI cranking divided by "multiplier" should get me close to CR,,,right?
getting the correct value for the multiplier is what I want. in the above example it's just local pressure plus 3.
I realize that atmospheric pressure will affect the results, a check of the local weather should get me close on that number.
yes, I'll convert the Hg to PSI. (if I can find my old physics book)
the +3 for mechanical action has me wondering,, is that a "standard" for a healthy engine?
any other variables?
if I use 175 psi test results, and 14.5psi local pressure, I'm at 650' above sea level,
175 PSI /(14.5 + 3) = 10 CR
I realize the accuracy may be a bit off, just trying to get close.
comments anybody?