Adding power door lock switches to existing Biltek CX-402 Conversion Kit just installed


CasinoBob

New member
Joined
Jul 29, 2019
Messages
3
Reaction score
0
Points
1
Location
Delaware
Vehicle Year
1999
Make / Model
Ford Ranger
Transmission
Manual
On my 1999 Mazda B3000 Ford Ranger) I just installed a Biltek CX-402 Conversion kit which consists of door lock actuators and key fobs to operate them. I also want to install door lock switches in the door panels but can't find any information on how to do it. I see that I can by door lock switches but can't find any instructions on how to wire them to the kit I just installed. Any help would be greatly appreciated.
 


Rock Auto 5% Discount Code: 248EE46702D889 Expires: October 1, 2019

RonD

Well-known member
Joined
Jun 2, 2012
Messages
13,475
Reaction score
343
Points
83
Location
canada
Vehicle Year
1994
Make / Model
Ford
Transmission
Manual
Welcome to TRS :)

You can't wire them to the controller, it doesn't have an external input, it gets a Wireless signal from the fob to lock or unlock

You can wire switches to the new door lock solenoids, but you will need to used 2 relays and a fuse, and the switches of course

I would see how much 2 more Fobs would cost and mount those to the doors


The door solenoids work on 12volts DC, DC means there is a + and - , this is important
Door solenoid has 2 wires
If one wire is + and the other wire is - then solenoid moves UP, if you reverse this so + wire is now - and - wire is now + then solenoid moves DOWN

So this is what the switches do, switch has 3 wires, wire for each relay, and one GROUND wire
One relay is for UnLock, one is for Lock

When relays are OPEN door solenoid wires are BOTH - (grounds)
When door switch activates UnLock relay it Closes making its Door Solenoid wire + , the other wire is still - so solenoid moves UP

Same for Lock, except other relay Closes and other wire is +

Both door solenoids would be wired to these relays, so its ALL UnLock or Lock
You will need 4 Diodes where you tie into the door solenoid wires to prevent a short when Fob activates door locks

You use 5 pin relays, because you need 87A pin
5amp fuse should be fine, 12v full time power to the relays for relay power and door solenoid power
 
Last edited:

CasinoBob

New member
Joined
Jul 29, 2019
Messages
3
Reaction score
0
Points
1
Location
Delaware
Vehicle Year
1999
Make / Model
Ford Ranger
Transmission
Manual
Welcome to TRS :)

You can't wire them to the controller, it doesn't have an external input, it gets a Wireless signal from the fob to lock or unlock

You can wire switches to the new door lock solenoids, but you will need to used 2 relays and a fuse, and the switches of course

I would see how much 2 more Fobs would cost and mount those to the doors


The door solenoids work on 12volts DC, DC means there is a + and - , this is important
Door solenoid has 2 wires
If one wire is + and the other wire is - then solenoid moves UP, if you reverse this so + wire is now - and - wire is now + then solenoid moves DOWN

So this is what the switches do, switch has 3 wires, wire for each relay, and one GROUND wire
One relay is for UnLock, one is for Lock

When relays are OPEN door solenoid wires are BOTH - (grounds)
When door switch activates UnLock relay it Closes making its Door Solenoid wire + , the other wire is still - so solenoid moves UP

Same for Lock, except other relay Closes and other wire is +

Both door solenoids would be wired to these relays, so its ALL UnLock or Lock
You will need 4 Diodes where you tie into the door solenoid wires to prevent a short when Fob activates door locks

You use 5 pin relays, because you need 87A pin
5amp fuse should be fine, 12v full time power to the relays for relay power and door solenoid power
Thanks for the information. I like your idea of getting two more key fobs. Easiest least expensive solution, and it won't look bad. Thanks again.
 


Top